Question

What is the mean absolute deviation of the data: 3, 7, 8, 12, 16, 18 of each number. I tried to take a picture but it is too blurry. But pls hurry hurry!!!​

Answer 1

`M = 4.67`

Explanation:

Given

`Data: 3, 7, 8, 12, 16, 18`

Required

The mean absolute deviation

Start by calculating the mean

`\bar x = (\sum x)/(n)`

`\bar x = (3+ 7+ 8+ 12+ 16+ 18)/(6)`

`\bar x = (64)/(6)`

`\bar x = 10.67`

The mean absolute deviation is then calculated using:

`M = (1)/(n)\sum\limits^n_(i=1)|x _i - \bar x|`

So, we have:

`M = (1)/(6)(|3 - 10.67| +|7 - 10.67| + |8 - 10.67| + |12 - 10.67| + |16 - 10.67| + |18 - 10.67|)`

`M = (1)/(6)(|-7.67| +|- 3.67| + |-2.67| + |1.33| + |5.33| + |7.33|)`

Remove absolute brackets

`M = (1)/(6)(7.67 +3.67 + 2.67 + 1.33 + 5.33 + 7.33)`

`M = (1)/(6)*28`

`M = 4.67`