What are the first three terms of a geometric sequence in which as = 25 and the common ratio is 5? 1 1 1 25'5 25,125,625 1 1 1 25'125 '625 O 125, 25, 5 Mark this …

Question

asked Nov 19, 2022 209k views

2 Answers

Aung Htet · Answer 1 · 2022-11-26T04:38:49+0000

Answer:

The first three terms are: 25, 125 and 625

Explanation:

Given

a =25; r = 5

Required

The first three terms

The nth term of a geometry progression is:

$T_n =ar^{n-1$

So, we have:

First term:
n = 1

$T_n =ar^{n-1$

$T_1 =25 * 5^{1-1$

T_1 =25 * 5^0

T_1 =25 * 1

T_1 =25

Second term:
n = 2

$T_n =ar^{n-1$

$T_2 =25 * 5^{2-1$

$T_2 =25 * 5^{1$

T_2 =25 * 5

T_2 =125

Third term:
n = 3

$T_n =ar^{n-1$

$T_3 =25 * 5^{3-1$

$T_3 =25 * 5^{2$

T_3 =25 * 25

T_3 =625