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What are the first three terms of a geometric sequence in which as = 25 and the common ratio is 5?

1 1
1
25'5
25,125,625
1 1 1
25'125 '625
O 125, 25, 5
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User Pyy
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4.5k points

2 Answers

2 votes

Answer: 25,125,625

Explanation:

edg 2

User Paul Liang
by
4.6k points
6 votes

Answer:

The first three terms are: 25, 125 and 625

Explanation:

Given


a =25; r = 5

Required

The first three terms

The nth term of a geometry progression is:


T_n =ar^{n-1

So, we have:

First term:
n = 1


T_n =ar^{n-1


T_1 =25 * 5^{1-1


T_1 =25 * 5^0


T_1 =25 * 1


T_1 =25

Second term:
n = 2


T_n =ar^{n-1


T_2 =25 * 5^{2-1


T_2 =25 * 5^{1


T_2 =25 * 5


T_2 =125

Third term:
n = 3


T_n =ar^{n-1


T_3 =25 * 5^{3-1


T_3 =25 * 5^{2


T_3 =25 * 25


T_3 =625

User Aung Htet
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