Step-by-step explanation:
Write the balance equation for the reaction taking place:
CO(g) + 2H2(g) ==> CH3OH ... balanced equation
Find the limiting reactant:
- moles CO present = 14 g x 1 mol CO / 28 g = 0.5 moles CO
- moles H2 present = 1.5 g x 2 mol H2 / 2 g = 0.75 moles H2O
Because according to the balanced equation it takes 2 moles H2 for every 1 mole CO, there isn't enough H2, so it is limiting and will dictate how much CH3OH can be made.
Mass of CH3OH produced = 0.75 moles H2 x 1 mol CH3OH / 2 mol H2 x 32 g CH3OH / mol = 12 g CH3OH