129k views
2 votes
The width of a triangle of 7 feet longer than its length. Find the dimensions of the rectangle such that the perimeter of the rectangle is 162 feet

User Alfy
by
7.7k points

1 Answer

0 votes

Answer:

Length = 37 feets

Width = 44 feets

Explanation:

Given that :

Length = l

Width, w = 7 + l

Perimeter , P of rectangle = 162

Recall:

Perimeter of a rectangle = 2(l + w)

P = 2(l + w)

162 = 2(l + (7 + l))

162 = 2(l + 7 + l)

162 = 2(7 + 2l)

162 = 14 + 4l

162 - 14 = 4l

148 = 4l

l = 148 / 4

l = 37 feets

Width = l + 7

Hence,

Width = 37 + 7 = 44 feets

User Sergey Reutskiy
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories