Question

The width of a triangle of 7 feet longer than its length. Find the dimensions of the rectangle such that the perimeter of the rectangle is 162 feet

Answer 1

Length = 37 feets

Width = 44 feets

Explanation:

Given that :

Length = l

Width, w = 7 + l

Perimeter , P of rectangle = 162

Recall:

Perimeter of a rectangle = 2(l + w)

P = 2(l + w)

162 = 2(l + (7 + l))

162 = 2(l + 7 + l)

162 = 2(7 + 2l)

162 = 14 + 4l

162 - 14 = 4l

148 = 4l

l = 148 / 4

l = 37 feets

Width = l + 7

Hence,

Width = 37 + 7 = 44 feets