Question

Can somebody help me on this problem please?

Answer 1

B. 1

Explanation:

`\lim_(x \to -3) √(x^2 - 8)`

Here we have

`\lim_(x \to -3) f(x)=f(x)`

Therefore

`\lim_(x \to -3) √(x^2 - 8) = \lim_(x \to -3) √((-3)^2 - 8) = \lim_(x \to -3) √(9 - 8) = \lim_(x \to -3) √(1)`

`\lim_(x \to -3) √(1)= \lim_(x \to -3) 1 = 1`