Question

A submarine travels 1.2 km due North from its base and then turns and travels due West for 5.8 km. How far away is the submarine from its base? Give your answer rounded to 1 DP.

Answer 1

5.9km

Explanation:

this would b solved using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c = hypotenuse

1.2² + 5.8² = c²

1.44 + 33.64 = c²

35.08 = c²

c = 5.9 km