Question

Which name best describes the polygon with vertices (0, 0), (4, 8), (12, 8), and (16, 0)? A) Triangle C) Trapezoid B) Square D) Pentagon

Answer 1

Answer: C. Trapezoid

Explanation:

Graph the points and you get a trapezoid!!!

Hope this helps!!!

Answer 2

C) Trapezoid

Explanation:

Given

`A = (0,0)`

`B = (4,8)`

`C = (12,8)`

`D=(16,0)`

Required

The possible shape

The above are 4 vertices.

Hence, the shape cannot be

(a) Triangle ---- it has 3 vertices

(b) Pentagon ---- it has 5 vertices

Calculate distance AB using distance formula

`AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2`

Where:

`A = (0,0)`

`B = (4,8)`

`AB = \sqrt{(0 - 4)^2 + (0 - 8)^2`

`AB = \sqrt{( - 4)^2 + ( - 8)^2`

`AB = \sqrt{16+64`

`AB = \sqrt{80`

`AB = 8.94`

Calculate distance BC using distance formula

`BC = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2`

Where:

`B = (4,8)`

`C = (12,8)`

`BC = \sqrt{(4 - 12)^2 + (8 - 8)^2`

`BC = \sqrt{(-8)^2 + (0)^2`

`BC = \sqrt{64 +0`

`BC = \sqrt{64`

`BC = 8`

Since

`AB \\e BC`

Then, the polygon is not a square

The last available option is (c) trapezoid