Question

What volume of 2.0M HCl is needed to prepare 0.50L of a 0.75M solution?
Please show your work

Answer 1

V = 0.5 L

Step-by-step explanation:

Given that,

The volume of HCl, V = 2 M

We need to find the volume of 2.0M HCl is needed to prepare 0.50L of a 0.75M solution.

Let n be the number of moles of HCl.

`n=c* V`

Where

c is molarity

`n=2* 0.5\\\\n=1\ mol`

Let V be the volume of the solution. So,

`V=(n)/(c)\\\\V=(1)/(2)\\\\V=0.5\ L`

So, the required volume of the solution is equal to 0.5 L.