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Tiffany and Dion are having a walking race. The equation and graph show the distance each person is from the starting line,

Tiffany's Distance
d = 2.5t, where d is the distance, in yards that Tiffany is from the starting line after t seconds
PLEASE ANSWER A., B. And C.

Tiffany and Dion are having a walking race. The equation and graph show the distance-example-1
User Heelara
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Answer:

Explanation:

Tiffany's distance is defined by the equation,

d = 2.5t

Here, d = distance of Tiffany from the starting line

t = time

a). d = 2.5t


(d)/(t)=2.5

Tiffany's rate = 2.5 yards per second

b). Since, slope of a line passing through two points
(x_1,y_1) and
(x_2,y_2) is given by,

Slope =
(y_2-y_1)/(x_2-x_1)

Therefore, slope of the line passing through two points (0, 10) and (10, 35)

=
(35-10)/(10-0)

= 2.5 yards per second

Dion's walking rate = 2.5 yards per second

Equation that defines the distance of Dione,

d = mt + b

Here, m = rate of the walking by Dione

b = y-intercept

Hence, equation will be,

d = 2.5t + 10

c). If d = 60 yards

For Tiffany,

d = 2.5t

60 = 2.5t

t = 24 seconds

For Dion,

d = 2.5t + 10

60 = 2.5t + 10

2.5t = 50

t = 20 seconds

Therefore, Dion will take less time and finish first.

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