Question

Tiffany and Dion are having a walking race. The equation and graph show the distance each person is from the starting line,

Tiffany's Distance
d = 2.5t, where d is the distance, in yards that Tiffany is from the starting line after t seconds
PLEASE ANSWER A., B. And C.

Answer 1

Explanation:

Tiffany's distance is defined by the equation,

d = 2.5t

Here, d = distance of Tiffany from the starting line

t = time

a). d = 2.5t

`(d)/(t)=2.5`

Tiffany's rate = 2.5 yards per second

b). Since, slope of a line passing through two points
`(x_1,y_1)` and
`(x_2,y_2)` is given by,

Slope =
`(y_2-y_1)/(x_2-x_1)`

Therefore, slope of the line passing through two points (0, 10) and (10, 35)

=
`(35-10)/(10-0)`

= 2.5 yards per second

Dion's walking rate = 2.5 yards per second

Equation that defines the distance of Dione,

d = mt + b

Here, m = rate of the walking by Dione

b = y-intercept

Hence, equation will be,

d = 2.5t + 10

c). If d = 60 yards

For Tiffany,

d = 2.5t

60 = 2.5t

t = 24 seconds

For Dion,

d = 2.5t + 10

60 = 2.5t + 10

2.5t = 50

t = 20 seconds

Therefore, Dion will take less time and finish first.