Question

How many moles are present in

a.12g of Nitrogen molecule.

b. the following particles of oxygen

`12.044 * {10}^(23)`


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Answer 1

Answer: (a) There are 0.428 moles present in 12 g of
`N_(2)` molecule.

(b) There are 2 moles present in
`12.044 * 10^(23)` particles of oxygen.

Step-by-step explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of
`N_(2)` is 28 g/mol so its number of moles are calculated as follows.

`No. of moles = (mass)/(molar mass)\\= (12 g)/(28 g/mol)\\= 0.428 mol`

So, there are 0.428 moles present in 12 g of
`N_(2)` molecule.

(b). According to the mole concept, 1 mole of every substance contains
`6.022 * 10^(23)` atoms.

Therefore, moles present in
`12.044 * 10^(23)` particles are calculated as follows.

`Moles = (12.044 * 10^(23))/(6.022 * 10^(23))\\= 2 mol`

So, there are 2 moles present in
`12.044 * 10^(23)` particles of oxygen.