A student has a sample of 1.42 moles of fluorine gas that is contained in a 28.1 L container at 305 K. What is the pressure of the sample?

Question

asked Mar 21, 2022 39.4k views

1 Answer

Rhyek · Answer 1 · 2022-03-25T19:26:52+0000

Answer:

P = 1.26 atm

Step-by-step explanation:

Given that,

The number of moles, n = 1.42 mol

Volume, V = 28.1 L

Temperature, T = 305 K

We need to find the pressure of the gas. The ideal gas law is as follows :

$PV=nRT\\\\P=(nRT)/(V)$

R = 0.0821 L-atm/mol-K

Put all the values,

$P=(1.42 * 0.0821* 305 )/(28.1 )\\\\P=1.26\ atm$

So, the pressure of the gas is 1.26 atm.