Question

A student has a sample of 1.42 moles of fluorine gas that is contained in a 28.1 L container at 305 K. What is the pressure of the sample?

Answer 1

P = 1.26 atm

Step-by-step explanation:

Given that,

The number of moles, n = 1.42 mol

Volume, V = 28.1 L

Temperature, T = 305 K

We need to find the pressure of the gas. The ideal gas law is as follows :

`PV=nRT\\\\P=(nRT)/(V)`

R = 0.0821 L-atm/mol-K

Put all the values,

`P=(1.42 * 0.0821* 305 )/(28.1 )\\\\P=1.26\ atm`

So, the pressure of the gas is 1.26 atm.