Question

1. A diode laser has a band gap of eV0, where V0 is a voltage. The laser has an efficiency of 30%, meaning 30% of the power input is converted to laser light output. We run an electrical current I through the diode, where I is in amps.a. What is the wavelength of the photons produced by the laser

Answer 1

Hence wavelength of the photons produced by the laser is

`(hc)/(eV_0)`

Step-by-step explanation:

Given

Efficiency of laser - 30%

As we know

`eV_0 = (hc)/(\Lambda)`

h = plank's constant

c = speed of light

eV0 = band gap

Hence wavelength of the photons produced by the laser is

`\Lambda= (hc)/(eV_0)`