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A gas diffuses 1/7 times faster than hydrogen gas (H2).

What is the molar mass of the gas?

100.10 g/mol
98.78 g/mol
86.68 g/mol
79.98 g/mol

User Zawhtut
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2 Answers

1 vote

Answer:

98.78 g/mol

Step-by-step explanation:

Just took the test

User Bechir
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4 votes

Answer: The molar mass of the gas is 9.878 g/mol.

Step-by-step explanation:

According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.


Rate = (1)/(√(M))

where,

M = molar mass of gas

As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.


(R_(1))/(R_(2)) = \sqrt{(M_(2))/(M_(1))}\\

where,


M_(1) = molar mass of hydrogen gas


M_(2) = molar mass of another given gas


R_(1) = rate of diffusion of hydrogen


R_(2) = rate of diffusion of another given gas =
(1)/(7)R_(1)

Substitute the values into above formula as follows.


(R_(1))/(R_(2)) = \sqrt{(M_(2))/(M_(1))}\\(R_(1))/((1)/(7)R_(1)) = \sqrt{(M_(2))/(2)}\\7 * 1.414 = M_(2)\\M_(2) = 9.878 g/mol

Thus, we can conclude that the molar mass of the gas is 9.878 g/mol.

User Drunkdolphin
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