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ANSWER IT HOW THE QUESTIONS ARE ASKED!! Thank you so much!!

ANSWER IT HOW THE QUESTIONS ARE ASKED!! Thank you so much!!-example-1
User Almas
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Answer:


(a)\ Pr = (2)/(5)


(b)\ Pr = (9)/(20)


(c)\ E(Orange) = 100


(d)\ E(Orange) = 62.5

Explanation:

Solving (a): Theoretical probability of green or yellow

Here, we consider the spinner itself

From the attached image, we have:


n= 5 --- i.e. 5 sections


Yellow = 1


Green = 1

So, the probability is:


Pr = P(Yellow)\ or\ P(Green)


Pr = (Yellow)/(n) + (Green)/(n)


Pr = (1)/(5) + (1)/(5)

Take LCM


Pr = (1+1)/(5)


Pr = (2)/(5)

Solving (b): Experimental probability of green or yellow

Here, we consider the result of the experiment

From the attached image, we have:


n= 40 --- i.e. 40 spins


Yellow = 12


Green = 6

So, the probability is:


Pr = P(Yellow)\ or\ P(Green)


Pr = (Yellow)/(n) + (Green)/(n)


Pr = (12)/(40) + (6)/(40)

Take LCM


Pr = (12+6)/(40)


Pr = (18)/(40)

Simplify


Pr = (9)/(20)

Solving (c): Expectation of orange outcomes in a spin of 500 times, theoretically.

Here, we consider the spinner itself

From the attached image, we have:


n= 5 --- i.e. 5 sections


Orange = 1

So, the probability of having an outcome of orange in 1 spin is:


Pr = P(Orange)


Pr = (Orange)/(n)


Pr = (1)/(5)

In 500 spins, the expectation is:


E(Orange) = Pr * 500


E(Orange) = (1)/(5) * 500


E(Orange) = 100

Solving (c): Expectation of orange outcomes in a spin of 500 times, base on experiments.

Here, we consider the spinner itself

From the attached image, we have:


n= 40 --- i.e. 40 spins


Orange = 5

So, the probability of having an outcome of orange is:


Pr = P(Orange)


Pr = (Orange)/(n)


Pr = (5)/(40)


Pr = (1)/(8)

In 500 spins, the expectation is:


E(Orange) = Pr * 500


E(Orange) = (1)/(8) * 500


E(Orange) = 62.5

User VAAA
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