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Analyze Corey’s work to find his error. What is Corey’s mistake? He substituted 80 for x instead of y. He should have added 88.21 to both sides. He should have rounded down to 32.1°F. He should have predicted about 40 swimmers when the temperature is 80°F.

User Rdnobrega
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2 Answers

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Answer:

A

Explanation:

I got it right on Edge

User Driscoll
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x is the temperature and y is the number of swimmers. If there are 80 swimmers, then y = 80 instead of x = 80

This is how Corey should have solved

y = 1.505*x - 88.21

80 = 1.505*x - 88.21 <--- replace y with 80

1.505*x - 88.21 = 80

1.505*x = 80 + 88.21 <--- add 88.21 to both sides

1.505*x = 168.21

x = 168.21/1.505 <--- divide both sides by 1.505

x = 111.767

x = 111.8

If there are 80 swimmers at the pool, then the possible outside temperature is roughly 111.8 degrees F. This temperature seems awfully large, so it's possible that Corey's regression equation has limited scope; in other words, it isn't too useful if x is outside a given interval

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Analyze Corey’s work to find his error. What is Corey’s mistake? He substituted 80 for-example-1
User Buqing
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