Find the points at which the graph of the equation has a vertical or horizontal tangent line. 81x^2 + 49y^2 + 1134x − 882y + 3969 = 0

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asked Jun 8, 2023 54.6k views

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Find the points at which the graph of the equation has a vertical or horizontal tangent line. 81x^2 + 49y^2 + 1134x − 882y + 3969 = 0

Mathematics
college

Harish Rachakonda asked

by Harish Rachakonda

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Answer:

882y,com hi

Explanation:

hi hi hi hi hi hi hi hi hi

Jules answered Jun 12, 2023

by Jules

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