19.5k views
0 votes
Help, so You pick a card at random. Without putting the first card back, you pick a second card at random. There are 3 cards, a 5 a 6 and a 7 What is the probability of picking a 5 and then picking a 6?

1 Answer

3 votes

Given:

There are 3 cards, a 5 a 6 and a 7.

You pick a card at random. Without putting the first card back, you pick a second card at random.

To find:

The probability of picking a 5 and then picking a 6.

Solution:

We have,

Total number of cards = 3

Number of card of 5 = 1

So, probability of getting a card of 5 is:


P(5)=\frac{\text{Number of card of 5}}{\text{Total number of cards}}


P(5)=(1)/(3)

After this selection, the remaining number of cards is 2. So, probability of getting a card of 6 in second draw is:


P(6)=\frac{\text{Number of card of 6}}{\text{Total number of remaining cards}}


P(6)=(1)/(2)

Now, the probability of picking a 5 and then picking a 6 is


P(\text{5 then 6})=P(5)* P(6)


P(\text{5 then 6})=(1)/(3)* (1)/(2)


P(\text{5 then 6})=(1)/(6)

Therefore, the probability of picking a 5 and then picking a 6 is
(1)/(6).

User Gilad Bar
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories