Answer:
The area of the shaded region is 11.606 square centimeters.
Explanation:
The area of the shaded region is obtained by subtracting the area of the triangle from the area of the circular section. The area of the triangle (
), in square centimeters, can be calculated by the Heron's formula:
(1)
(2)
Where:
,
,
- Lengths of the sides of the triangle, in centimeters.
- Semiperimeter, in centimeters.
If we know that
and
, then the area of the triangle is:
![s = (10.50\,cm + 2\cdot (9.28\,cm))/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/a5iby469zy7qrhsn2jhhat8wg1ryzvxoat.png)
![s = 14.53\,cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/5g3sj18u2m22seijog349cf4z36pynqmxu.png)
![A_(t) = \sqrt{(14.53\,cm)\cdot (14.53\,cm - 10.50\,cm)\cdot (14.53\,cm - 9.28\,cm)^(2)}](https://img.qammunity.org/2022/formulas/mathematics/high-school/6ktygn16prt9i04qmmxisqpkk77cdvea70.png)
![A_(t) \approx 40.174\,cm^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/2seoka6z5ysxp89z64uxl5q5g0i4b76qfn.png)
And the area of the circular section (
), in square centimeters, is determined by the following formula:
(3)
Where:
- Radius of the circle, in centimeters.
- Internal angle, in sexagesimal degrees.
If we know that
and
, then the area of the circular section is:
![A_(c) = \left((68.9)/(360)\right)\cdot \pi\cdot (9.28\,cm)^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/khrkapg0nlgww8cw8mmt4cifo2vku22nmx.png)
![A_(c) \approx 51.780\,cm^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/p5nm5agcvkukqjvwtltbugccw7y6mr3biu.png)
Finally, the area of the shaded region (
), in square centimeters, is:
(4)
![A = 51.780\,cm^(2)- 40.174\,cm^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/xdlcgezbis0e6haf3jjzxtvcckm3livbjv.png)
![A = 11.606\,cm^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/m41aivpwd93ce1b0c6t5l73bwe5cji5yya.png)
The area of the shaded region is 11.606 square centimeters.