Question

A 996.9 g sample of ethanol undergoes a temperature change of -70.98 °C while releasing 62.9

calories of heat. What is the specific heat capacity of ethanol?

Answer 1

`c=3.71\ J/g^(\circ) C`

Step-by-step explanation:

Given that,

Mass of sample, m = 996.9 g

The change in temperature of the sample,
`\Delta T=-70.98^(\circ)C`

Heat produced, Q = 62.9 calories = 263173.6 J

The heat released by a sample due to change in temperature is given by :

`Q=mc\Delta T`

Where

c is the specific heat capacity

So,

`c=(Q)/(m\Delta T)\\\\c=(263173.6)/(996.9* 70.98)\\\\c=3.71\ J/g^(\circ) C`

So, the specific heat of ethanol is equal to
`3.71\ J/g^(\circ) C`.