Question

Area plz answrr me sjsksjvdosnsbdo

Answer 1

Given:

The diagram of a figure with sides 14 ft, 30 ft, 21 ft and 18 ft.

To find:

The area of the figure.

Solution:

From the given figure it is clear that if we cut a corner of a rectangle, then we get the same figure.

The sides of a the rectangle are 30 ft and 21 ft.

The height of the triangular part is (30 ft - 18 ft) and the base is (21 ft - 14 ft).

So, the height of the triangular part is 12 ft and the base is 7 ft.

The area of the rectangle is:

`A_1=length* width`

`A_1=30* 21`

`A_1=630`

The area of the triangular part is:

`A_2=(1)/(2)* base * height`

`A_2=(1)/(2)* 12 * 7`

`A_2=6 * 7`

`A_2=42`

Now, the area of the given figure is:

`A=A_1-A_2`

`A=630-42`

`A=588`

Therefore, the area of the given figure is 588 sq. ft.