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Answer:
Explanation:
The distance from the cheetah's starting point (in feet) can be modeled by ...
for the cheetah
c = 102.6t
for the gazelle
g = 73.3t +500
When these are equal, the cheetah will have caught the gazelle:
c = g
102.6t = 73.3t +500
29.3t = 500
t = 500/29.3 ≈ 17.1 . . . . . . seconds
The distance at that time is ...
c = 102.6(17.0648) ≈ 1750.9 . . . . feet
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Additional comment
The cheetah can maintain top speed only for about 10 seconds. At 500 ft distance, the gazelle is pretty safe.