Answer:
531.45 mL
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 500 mL
Initial temperature (T₁) = 45 °C
Final temperature (T₂) = 65 °C
Final volume (V₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 45 °C
Initial temperature (T₁) = 45 °C + 273
Initial temperature (T₁) = 318 K
Final temperature (T₂) = 65 °C
Final temperature (T₂) = 65 °C + 273
Final temperature (T₂) = 338 K
Finally, we shall determine the final volume of the gas. This can be obtained as follow:
Initial volume (V₁) = 500 mL
Initial temperature (T₁) = 318 K
Final temperature (T₂) = 338 K
Final volume (V₂) =?
V₁/T₁ = V₂/T₂
500 / 318 = V₂ / 338
Cross multiply
318 × V₂ = 500 × 338
318 × V₂ = 169000
Divide both side by 318
V₂ = 169000 / 318
V₂ = 531.45 mL
Therefore, the new volume of the gas is 531.45 mL