Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
By using Pythagoras law
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
So another side's length is 10cm
Exercise 2:
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√28or 2√7 0r 5.29 or 5.3 m
Explanation:
[Note: thanks for translating]