Question

In this experiment, you will need to prepare 250.0 mL of 0.100 M KCl(aq) solution. Determine the mass in grams of potassium chloride required to prepare this solution. Type your numerical answer (no units) in the box below. Even though the number of significant figures is limited to three by the inputs, please report your answer to four significant figures.

Answer 1

Answer: The mass in grams of potassium chloride required to prepare this solution is 1.862 grams

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in ml

moles of
`KCl` =
`\frac{\text {given mass}}{\text {Molar mass}}=(xg)/(74.5g/mol)`

Now put all the given values in the formula of molality, we get

`0.100=(x* 1000)/(74.5g/mol* 250.0ml)`

`x=1.862g`

Therefore, the mass in grams of potassium chloride required to prepare this solution is 1.862 grams