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Determine which of the two acute angles has a cosine of 4/5.

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Answer:

CosA = 4/5

Explanation:

The acute angle with cosine of 4/5

Recall from trigonometry ;

Cosine = Adjacent / hypotenus

From the right angled triangle Given:

For angle A :

Opposite = BC = 8

Hypotenus = AC = 10

Cos A = BC / AC = 8 /10 = 4 /5

CosA = 4/5

For C :

Opposite = AB = 6

Hypotenus = AC = 10

Cos C = 6 /10 = 3 /5

Determine which of the two acute angles has a cosine of 4/5.-example-1
User Wileymab
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