Question

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three resistors of 20. ohms, 30. ohms, and 60. ohms, respectively, are connected in series with a battery. a current of 2.0 amperes will flow through this circuit when the potential difference of the battery is a. 20.V b. 220 V c. 110 V d. 10.V.

Answer 1

In a series circuit, the total resistance is the sum of the individual resistances. The voltage in the circuit is equal to the current multiplied by the total resistance. Therefore, the answer is 220 V.

Step-by-step explanation:

In a series circuit, the total resistance is simply the sum of the individual resistances. In this case, the three resistors have resistances of 20 ohms, 30 ohms, and 60 ohms, respectively. Therefore, the total resistance in the circuit is 20 + 30 + 60 = 110 ohms.

According to Ohm's law, the current in a circuit is equal to the voltage divided by the resistance. In this case, the current is 2.0 amperes, and the total resistance is 110 ohms. Therefore, the voltage must be the current multiplied by the resistance: V = I * R = 2.0 A * 110 ohms = 220 V.

Therefore, the correct answer is (b) 220 V.

Answer 2

b. 220 V

Step-by-step explanation:

Let resistors be R1, R2, and R3 respectively.

Given the following data;

R1 = 20 ohms

R2 = 30 ohms

R3 = 60 ohms

Current = 2 Amperes

To find the voltage;

First of all, we would determine the total effective resistance (RT).

For series circuit;

RT = R1 + R2 + R3

RT = 20 + 30 + 60

RT = 110 Ohms

Next, we find the voltage using the formula;

Voltage = current * resistance

Voltage = 2 * 110

Voltage = 220 Volts