Question

How much ammonia would it take to neutralize 5ml of apple cider and 5ml of white vinegar if the ammonia had a molarity of 0.25?

Answer 1

`m_(NH_3)=0.0213gNH_3`

Step-by-step explanation:

Hello there!

In this case, since it is known that the reaction between ammonia and acetic acid is:

`CH_3COOH+NH_3\rightarrow CH_3COONH_4`

It is possible for us to realize that the mole ratio of acetic acid (vinegar) to ammonia is 1:1, that is why we can relate the concentrations as follows:

`M_(acid)V_(acid)=M_(base)V_(base)\\\\`

In such a way, by knowing that the volume of these two are the same, we infer that their concentrations is also de same; and therefore, the mass of ammonia is calculated as:

`m_(NH_3)=0.005L*0.25(molNH_3)/(L)*(17.04gNH_3)/(1molNH_3)\\\\m_(NH_3)=0.0213gNH_3`

Regards!