Given:
The equation of the trend line is:
![y=-0.36x+12.6](https://img.qammunity.org/2022/formulas/mathematics/high-school/da0a862a5kokic5z39gwqdjnvmn1dolhev.png)
In this equation y represents the wind chill and x represents the wind speed.
To find:
The wind chill at 51 mi/h.
Solution:
We have,
![y=-0.36x+12.6](https://img.qammunity.org/2022/formulas/mathematics/high-school/da0a862a5kokic5z39gwqdjnvmn1dolhev.png)
Putting
, we get
![y=-0.36(51)+12.6](https://img.qammunity.org/2022/formulas/mathematics/high-school/sgc409ea54ajhq1bt813hexigglj0qwoxf.png)
![y=-18.36+12.6](https://img.qammunity.org/2022/formulas/mathematics/high-school/99toecij2n154mznf9yv4le1scbcx911g0.png)
![y=-5.76](https://img.qammunity.org/2022/formulas/mathematics/high-school/bpduear8qk9b4kwbicphjylyf3nj2rdv8u.png)
Round the answer to the nearest degree.
![y\approx -6^\circ](https://img.qammunity.org/2022/formulas/mathematics/high-school/ukf51gwrq6vuh2ni7uw3wfni41uc8bhhqj.png)
Therefore, the wind chill at wind speed 51 mi/h is -6°.