Final answer:
To address the photoelectric effect in aluminum, we determined the maximum kinetic energy of photoelectrons (2.27 eV), discussed how to calculate their maximum speed, and outlined the method to find the wavelength of the incident monochromatic light using the stopping potential and the work function.
Step-by-step explanation:
The student is asking about the photoelectric effect in aluminum which involves concepts of physics. To solve these problems, one needs to use Einstein's photoelectric equation and basic principles of energy and momentum.
Maximum Kinetic Energy
The maximum kinetic energy (Kmax) of the photoelectrons can be determined using the equation Kmax = eV, where e is the charge of an electron and V is the stopping potential. Thus, Kmax = 2.27 eV.
Maximum Speed of Photoelectrons
To determine the maximum speed (vmax) of the photoelectrons, we can use the equation Kmax = (1/2)mv2, where m is the mass of an electron. By plugging in the values, we can solve for vmax.
Wavelength of Incident Light
The wavelength of the incident light can be found using Einstein's photoelectric equation, hf = φ + Kmax, where h is Planck's constant, f is the frequency of the light, and φ is the work function. With the given work function, and Kmax, we can determine the frequency and corresponding wavelength.