Question

Determine the equation of a circle graphed below

Answer 1

The equation of the circle is
`(x-h)^(2) +(y-k)^(2) =r^(2)`

• (h,k) center of the circle --> (-6, 6)
• r is the radius -->
  `√((-5--6)^2 + (9-6)^2) = √(1 +9) =√(10)`

Thus the equation of the circle is:

`(x+6)^(2) +(y-6)^2=10`

Hope that helps!