Question

What is the value for AG at 300 K if AH = 27 kJ/mol and AS = 0.09 kJ/(mol-K)?

O

A. AG = 54 kJ/mol

O

B. AG=-18 kJ/mol

O

C. AG= 0 kJ/mol

O

D. AG = 27 kJ/mol

Answer 1

0 kJ/mol

Step-by-step explanation:

Step 1: Given data

• Enthalpy change (ΔH): 27 kJ/mol

• Entropy change (ΔS): 0.09 kJ/mol.K

• Absolute temperature (T): 300 K

Step 2: Calculate the Gibbs free energy change (ΔG)

We can calculate the Gibbs free energy change using the following expression.

ΔG = ΔH - T × ΔS

ΔG = 27 kJ/mol - 300 K × 0.09 kJ/mol.K = 0 kJ/mol

Since ΔG = 0 kJ/mol, the process in not spontaneous nor non-spontaneous.