Question

A gas occupies 12.5 ft at - 173 °C. At what Celsius temperature will its volume be 16.0

it? Assume that pressure remains constant

Answer 1

T₂ = 128.19 K

Step-by-step explanation:

Given that,

The initial volume, V₁ = 12.5 ft³

Initial temperature, T₁ = -173 °C = 100.15 K

Final volume, V₂ = 16 ft³

We need to find the new temperature. The relation between temperature and volume is given by :

`V\propto T\\\\(V_1)/(V_2)=(T_1)/(T_2)`

Put all the values,

`T_2=(T_1V_2)/(V_1)\\\\T_2=(100.15* 16)/(12.5)\\\\T_2=128.19\ K`

So, the new temperature is 128.19 K.