36.9k views
0 votes
The graph of h(x)=-x^2+4x+4​

User Naresh
by
7.0k points

1 Answer

1 vote

Answer:

Explanation:

the coefficients of this quadratic are -1, 4 and 4, and so the discriminant b^2 - 4ac works out to 16 - 4(-1)(4), or 0. Thus this graph has two real, equal roots which are the same point on the graph, the vertex, the maximum of the function.

Letting x = 0, we find that y is 4. Thus, the y-intercept is (0, 4). Plot this.

Using the formula x = -b / [2a], we find the axis of symmetry:

x = -4 / [2*(-1)] = -4 / [-2] = +2

The axis of symmetry is the vertical line x = 2.

At x = 2, y = -(2)^2 + 4(2) + 4, OR -4 + 8 + 4, or 0.

The vertex and maximum value are (2, 0). The graph touches the x-axis in only one place.

Draw the axis of symmetry x = 2. Plot the vertex (2, 0) and the y-intercept. Reflect the y-intercept about the axis of symmetry to obtain a second point on the graph at the same y-value as (0, 4).

User Gergely Bacso
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.