Solve for x round to the nearest tenth. hurry!!!

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asked Mar 27, 2022 208k views

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Solve for x round to the nearest tenth. hurry!!!

Mathematics
high-school

Howell asked

by Howell

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Answer:

Law of cosines:

${x}^(2) = {a}^(2) + {b}^(2) - 2ab \cos( \gamma ) \\ = {12}^(2) + {15}^(2) - 2(12)(15) \cos(144) \\ = 144 + 225 - 360( - 0.809) \\ = 660.246 \\ x = 25.7$

Submonoid answered Apr 2, 2022

by Submonoid

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