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Find the greatest number that divides 1626, 1950 and 2274 leaving a remainder of 6 in each case? Please help

1 Answer

6 votes

Answer:

The common divisor that leaves a reminder of 6 is 324

Explanation:

Given

1626, 1950 and 2274

Required

Common divisor that leaves a remainder of 6

First, we subtract 6 from each number


1626 - 6 = 1620


1950 - 6 =1944


2274 - 6 = 2268

Next, we find the common divisor of 1620, 1944, 2268


1620 \to 2 * 2 *3 * 3*3*3*5


1944 \to 2 * 2 * 2 * 3 * 3 * 3 * 3 * 3


2268 \to 2 * 2 * 3 * 3 * 3 * 3 * 7

The common factors are:


Common = 2 * 2 * 3 * 3 * 3 * 3


Common = 324

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