Answer:
The common divisor that leaves a reminder of 6 is 324
Explanation:
Given
1626, 1950 and 2274
Required
Common divisor that leaves a remainder of 6
First, we subtract 6 from each number
![1626 - 6 = 1620](https://img.qammunity.org/2022/formulas/mathematics/high-school/k1dtz9giuh4ye76onomz204s7gnt0i3iku.png)
![1950 - 6 =1944](https://img.qammunity.org/2022/formulas/mathematics/high-school/hcxj8sb04byhyyhbo1zvtl7uouy08917lp.png)
![2274 - 6 = 2268](https://img.qammunity.org/2022/formulas/mathematics/high-school/2vgrlv43bpvx7kv4ltmb0cz9j55ecbqzg9.png)
Next, we find the common divisor of 1620, 1944, 2268
![1620 \to 2 * 2 *3 * 3*3*3*5](https://img.qammunity.org/2022/formulas/mathematics/high-school/16pfa7jxqs9rhdvmc29ypomdgcn8vse4bx.png)
![1944 \to 2 * 2 * 2 * 3 * 3 * 3 * 3 * 3](https://img.qammunity.org/2022/formulas/mathematics/high-school/s99if5jinundx4g2ypfrp435ebu6h6d7wl.png)
![2268 \to 2 * 2 * 3 * 3 * 3 * 3 * 7](https://img.qammunity.org/2022/formulas/mathematics/high-school/yxj1go1ed60e5t0n34z8wfmpcljgvb5vv7.png)
The common factors are:
![Common = 2 * 2 * 3 * 3 * 3 * 3](https://img.qammunity.org/2022/formulas/mathematics/high-school/88snbhk5lz34z3y6eg4qx311of6umlp3m4.png)
![Common = 324](https://img.qammunity.org/2022/formulas/mathematics/high-school/xg5s40woqq26teqgw6bkbu9s8jhbn9jwiu.png)