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What is the diameter of a sphere with a volume of 18174 ft^3 to the nearest tenth of a foot?

1 Answer

5 votes

Answer:

Diameter = 33 feet

Explanation:

Diameter = 2 x radius

Given that the volume = 18174
ft^(3), then;

Volume of sphere =
(4)/(3)
\pi
r^(3)

where r is the radius of the sphere.

Thus,

18174 =
(4)/(3) x
(22)/(7) x
r^(3)

=
(88)/(21)
r^(3)

18174 x 21 = 88
r^(3)

381654 = 88
r^(3)


r^(3) =
(381654)/(88)

= 4336.9773

r =
\sqrt[3]{4336.9773}

r = 16.3078

The diameter of the sphere = 2 x 16.3078

= 32.6156

= 33 feet

User Nrhode
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