Question

Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.

Answer 1

`6+ √(29),6-√(29)`

Explanation:

The given quadratic equation is
`x^2-12x+7=0`

The general form of quadratic equation is given by :

`ax^2+bx+c=0`

Comparing both the equations,

a = 1, b = -12 and c = 1

The solution of a quadratic equation is given by :

`x=(-b\pm √(b^2-4ac) )/(2a)`

Put all the values,

`a=(-(-12)\pm √((-12)^2-4* 1* 7) )/(2(1))\\\\=(12\pm √(116))/(2)\\\\=(12\pm 2√(29))/(2)\\\\=6\pm √(29)`

So, the solutions of the given equation is
`6+ √(29),6-√(29)`. Hence, the correct option is (d).