5L of air at-50 C is warmed to 100 C. What is the new volume?

asked Nov 5, 2022 55.9k views

1 vote

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2 votes

Answer:

V2 = 5.8 L

Step-by-step explanation:

T1 = 50°C = 323 K

V1 = 5L

T2 = 100°C = 373 K

V2 =?

According to Charles's law,

V1/T1 = V2/T2

---> V2 = (T2/T1)V1 = (373K/323K)(5 L)

= 5.8 L

FeatureCreep answered Nov 10, 2022

2.7k points

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