Answer:
Option D. It quadruples
Step-by-step explanation:
Let the initial voltage be V.
Let the initial power be P.
We shall determine the final power of the circuit as follow:
Initial voltage (V₁) = V
Initial power (P₁) = P
Final voltage (V₂) = double the initial voltage = 2P
Final power (P₂) =?
NOTE: Resistor (R) is constant
P = V² / R
Cross multiply
PR = V²
Divide both side by P
R = V² / P
Thus
V²₁ / P₁ = V²₂ / P₂
V² / P = (2V)² / P₂
V² / P = 4V² / P₂
Cross multiply
V² × P₂ = P × 4V²
Divide both side by V²
P₂ = P × 4V² / V²
P₂ = P × 4
P₂ = 4P
Thus, the power will be four times the initial power i.e quadruple.