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Given 750 g of oxygen gas and chlorine gas and an excess of the other reactants, how much potassium chloride (grams) will be produced? 2MnO2 + 4KOH + O2 + Cl2 -> 2KMnO4 + 2KCl + 2H20 must show work
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Given 750 g of oxygen gas and chlorine gas and an excess of the other reactants, how much potassium chloride (grams) will be produced?

2MnO2 + 4KOH + O2 + Cl2 -> 2KMnO4 + 2KCl + 2H20
must show work

User Cheatah
by
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1 Answer

4 votes

Answer:

=2h20−2kmno4+2mno2+2ckl+cl2+4hko+o2

Step-by-step explanation:

step-by-step.

2mno2+4koh+o2+cl2−2kmno4+2kcl+2h20

=2mno2+4hko+o2+cl2+−2kmno4+2ckl+2h20

User Leidolf
by
4.1k points
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