Question

How to solve the Quadratic formul​

Answer 1

The answer is x=-6, x=8

Explanation:

I recommend using the quadratic formula to solve this problem.

x^2=a

-2x=b

-48=c

Plug it into the quadratic formula.

New equation:
`(2+-√((-2)^2-4(1)(-48)))/(2(1))`

Simplify

Equation:
`(2+-√(4+192))/(2)`

Add 4 and 192.

Equation:
`(2+-√(196))/(2)`

Do the square root of 196.

Equation:
`(2+-14)/(2)`

Make into two different equations.

Equation 1:
`(2+14)/(2)`

Equation 2:
`(2-14)/(2)`

Solve the two equations and you will get -6 and 8. Hope this helps!

Answer 2

`\huge \boxed{\mathbb{QUESTION} \downarrow}`

• Solve using the quadratic formula ⇨ x² - 2x - 48 = 0.

`\large \boxed{\mathbb{ANSWER \: WITH \: EXPLANATION} \downarrow}`

`\sf \: x ^ { 2 } - 2 x - 48 = 0`

All equations of the form ax² + bx + c = 0 can be solved using the quadratic formula:
`\sf \frac{-b±\sqrt{b^(2)-4ac}}{2a}`. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

`\sf \: x^(2)-2x-48=0`

This equation is in standard form: ax² + bx + c = 0 Substitute 1 for a, -2 for b and -48 for c in the quadratic formula.

`\sf \: x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^(2)-4\left(-48\right)}}{2} \\`

Square -2.

`\sf \: x=(-\left(-2\right)±√(4-4\left(-48\right)))/(2) \\`

Multiply -4 times -48.

`\sf \: x=(-\left(-2\right)±√(4+192))/(2) \\`

Add 4 to 192.

`\sf \: x=(-\left(-2\right)±√(196))/(2) \\`

Take the square root of 196.

`\sf \: x=(-\left(-2\right)±14)/(2) \\`

The opposite of -2 is 2.

`\sf \: x=(2±14)/(2) \\`

Now solve the equation
`\sf\:x=(2±14)/(2)` when ± is plus. Add 2 to 14.

`\sf \: x=(16)/(2) \\`

Divide 16 by 2.

`\boxed{ \boxed{ \bf \: x=8 }}`

Now solve the equation
`\sf\:x=(2±14)/(2)` when ± is minus. Subtract 14 from 2.

`\sf \: x=(-12)/(2) \\`

Divide -12 by 2.

`\boxed{\boxed{ \bf \: x=-6 }}`

The equation is now solved.

`\underline{ \bf \: x=8 }\\ \underline{ \bf \: x=-6 }`