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An amusement park has a two merry-go-rounds. The first merry-go-round has a circular platform with a diameter of 13 meters. The second merry-go-round has a circular platform with a diameter of 19 meters. What is the difference between the areas of the larger and smaller merry-go-round’s platform?

User Stenix
by
4.6k points

2 Answers

3 votes

Answer

150.72 m2

Explanation:

Find the radius of the larger

merry-go-round.

19^2 = 9.5

Substitute 9.5 for r in the formula for the

area of a circle.

A-n • 9.52

= 71 -90.25

- 283.385

Find the radius of the smaller

merry-go-round.

13-^-2-6.5

Substitute 6.5 for r in the formula for the

area of a circle.

A~n • 6.52

= n - 42.25

-132.665

Subtract the area of the smaller merry go-round from the area of the larger

merry-go-round.

283.385 - 132.665 = 150.72

User Shine J
by
4.7k points
2 votes

Answer:

150.72

Explanation:

Area of circle formula is r²π

Do find radius you do d/2, diameter/2. 13/2= 6.5

6.5 * 6.5 = 42.25

π is also known as 3.14

42.25 * 3.14 = 132.665

That is the area of the smaller one.

For the larger one, 19/2 = 9.5

9.5 * 9.5 = 90.25

90.25 * 3.14= 283.385

Now you subtract both of them and the difference is 150.72.

Hope this helps !!

-Ketifa

User FMK
by
4.2k points