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Which equation has no real solutions?

a. -2x^2=-168
b. 4x^2+76=32
c. 25x^2=1
d. 43-x^2=12

1 Answer

3 votes

Answer:


B. 4x^2+76=32

Explanation:


In ~ option~ B


4x^2+76=32\\


4x^2=-76+32


4x^2=-44


x^2=-44/4=-11


x^2=-11

A square of any real number can't be a negative integer.

So, Option B is your answer


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hope it helps..

have a great day!!

User Barguast
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