Question

The volume of a sample of nitrogen gas at a temperature of 291K and 1.0 x 105 Pascals was 3.5 x 10-2m3. Calculate the temperature at which the volume of the gas would be 2.8 x 10-2m3 at 1.0 x 105pascals.

Answer 1

Answer:
`232.8\ K`

Step-by-step explanation:

Given

The volume of Nitrogen gas is
`V_1=3.5* 10^(-2)\ m^3`

Pressure is
`P_1=10^5\ Pa`

Temperature
`T_1=291\ K`

When the pressure and temperature changes i.e.

`P_2=10^5\ Pa`

`V_2=2.8* 10^(-2)\ m^3`

Temperature is given by

`\Rightarrow (P_1V_1)/(T_1)=(P_2V_2)/(T_2)\\\\\Rightarrow T_2=(P_2V_2)/(P_1V_1)* T_1`

Insert values

`\Rightarrow T_2=(2.8* 10^(-2)* 10^5)/(3.5* 10^(-2)* 10^5)* 291\\\\\Rightarrow T_2=291* 0.8\\\Rightarrow T_2=232.8\ K`