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Function f (x) = 25x/x + 3 has a discontinuity at x = –3. What are Limit of f (x) as x approaches negative 3 minus and Limit of f (x) as x approaches negative 3 plus?

User Jimena
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2 Answers

3 votes

Answer: C

Explanation:

Edge

User Bboydflo
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4 votes

Answer:

x approaches negative 3 to the right:
lim_(x\to -3^(+))=-\infty

x approaches negative 3 to the left:
lim_(x\to -3^(-))=\infty

Explanation:

The function we have is:


f(x)=(25x)/(x+3)

We have an asymptote at x = -3.

The limit of the function when x approaches negative 3 to the right will be:


lim_(x\to -3^(+))=(25x)/((-3)+3)=-\infty

It is because the function is decreasing from right to left.

And the limit of the function when x approaches negative 3 to the left will be:


lim_(x\to -3^(-))=(25x)/((-3)+3)=\infty

It is because the function is decreasing from left to right.

I hope it helps you!

User Denee
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