219k views
5 votes
In a pile of coins, there are 7 more quarters than nickels. If there is a

total of $2.65 in coins, how many total coins are there? How many
of each type of coin is in the pile? Guess, check, and revise to solve

2 Answers

3 votes

Answer:

Explanation:

we only have to have 7 more quarters than nickels.. so put one nickel and 8 quarters

that's $2.05

now make up the rest to make 2.65

add 6 dimes and you've got it :)

1 nickel

6 dimes

8 quarters

User Ben Shmuel
by
4.2k points
6 votes

Answer:

Explanation:

Let x = to the number of nickels.

Let x + 7 = the number of quarters.

So multiply x by .05 to find out how much the nickles are worth and

multiply x + 7 by .25 to find out how much the quarters are worth.

Then add them together to get the total and solve.

.05x + .25(x + 7) = 2.65

.05x + .25x + 1.75 = 2.65

.30x + 1.75 = 2.65

Subtract 1.75 from each side of the equation.

.30x = .90

x = 3

x + 7 = 10

So 10 is the number of quarters.

User Raphael K
by
4.8k points